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December 18, 2014

December 18, 2014

Posted by **keith** on Monday, February 7, 2011 at 8:19pm.

3x^2+5x-12=0

(3x+4)(x-3)

-4 +3

x=-4 x=3

now i need to solve by the form x^2=k

How do I do that?

- math -
**helper**, Monday, February 7, 2011 at 8:39pm3x^2 + 5x - 12 = 0

This cannot be factored

This can be solved by completing the square or using the quadratic formula.

(3x + 4)(x - 3) = 3x^2 - 5x - 12

Does not equal 3x^2 + 5x - 12

- math -
**Reiny**, Monday, February 7, 2011 at 9:15pmjust switch your signs

3x^2+5x-12=0

(3x-4)(x+3) = 0

so 3x-4 = 0 or x+3 = 0

x = 4/3 or x = -3

your version would give a middle term of -5x

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