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February 1, 2015

February 1, 2015

Posted by **Sandy** on Monday, February 7, 2011 at 1:59pm.

f(x) = 3 - |x - 2| for [-1, 5]

if so, find c.

if not, tell why.

- AP Calculus -
**MathMate**, Monday, February 7, 2011 at 6:34pmRolle's theorem states that:

"Suppose that y=f(x) is continuous at every point of the closed interval [a,b] and*differentiable*at every point of its interior (a,b). If

f(a)=f(b),

then there is at least one number c in (a,b) at which f'(c)=0.

Here all conditions are satisfied except one. It is not differentiable at x=2, so Rolle's theorem does not apply. Differentiable means that f'(x) exists, but f'(2) is an interior point of (-1,5) and f'(2) does not exist. Check the graph below. Post if more help is required.

http://img28.imageshack.us/img28/9139/1297105145.png

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