Posted by Thakgalo sakwana on .
An object is projected vertically upwards and returns to the point of projection 12s later. Ignore air resistance and determine the velocity with which it was projected?

Physical science 
Thakgalo sakwana,
Vf=Vi +at
Vf=0, Vi=?, a=9.8 remeber time taken to go up is equal to the time taken to go back to the point of projectile.. THEREFORE t=6
Vf=Vi +at
(0)=Vi +(9.8)(6)
Vi=58.8m/s
***[OR]***
Vf=Vi +at
Vf=Vi, Vi=?, a=9.8, t=12
(Vi)=Vi +(9.8)(12)
2Vi= 117.6
Vi=58.8m/s
if u've any question call 0723624826 
Physical science 
Erick,
It corect