Physical science
posted by Thakgalo sakwana on .
An object is projected vertically upwards and returns to the point of projection 12s later. Ignore air resistance and determine the velocity with which it was projected?

Vf=Vi +at
Vf=0, Vi=?, a=9.8 remeber time taken to go up is equal to the time taken to go back to the point of projectile.. THEREFORE t=6
Vf=Vi +at
(0)=Vi +(9.8)(6)
Vi=58.8m/s
***[OR]***
Vf=Vi +at
Vf=Vi, Vi=?, a=9.8, t=12
(Vi)=Vi +(9.8)(12)
2Vi= 117.6
Vi=58.8m/s
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