Posted by **Thakgalo sakwana** on Monday, February 7, 2011 at 12:45pm.

An object is projected vertically upwards and returns to the point of projection 12s later. Ignore air resistance and determine the velocity with which it was projected?

- Physical science -
**Thakgalo sakwana**, Monday, August 1, 2011 at 3:50am
Vf=Vi +at

Vf=0, Vi=?, a=-9.8 remeber time taken to go up is equal to the time taken to go back to the point of projectile.. THEREFORE t=6

Vf=Vi +at

(0)=Vi +(-9.8)(6)

Vi=58.8m/s

***[OR]***

Vf=Vi +at

Vf=-Vi, Vi=?, a=-9.8, t=12

(-Vi)=Vi +(-9.8)(12)

-2Vi= -117.6

Vi=58.8m/s

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- Physical science -
**Erick**, Monday, April 22, 2013 at 11:08am
It corect

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