Posted by Thakgalo sakwana on Monday, February 7, 2011 at 12:45pm.
An object is projected vertically upwards and returns to the point of projection 12s later. Ignore air resistance and determine the velocity with which it was projected?

Physical science  Thakgalo sakwana, Monday, August 1, 2011 at 3:50am
Vf=Vi +at
Vf=0, Vi=?, a=9.8 remeber time taken to go up is equal to the time taken to go back to the point of projectile.. THEREFORE t=6
Vf=Vi +at
(0)=Vi +(9.8)(6)
Vi=58.8m/s
***[OR]***
Vf=Vi +at
Vf=Vi, Vi=?, a=9.8, t=12
(Vi)=Vi +(9.8)(12)
2Vi= 117.6
Vi=58.8m/s
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Physical science  Erick, Monday, April 22, 2013 at 11:08am
It corect
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