Posted by shay on Monday, February 7, 2011 at 12:15pm.
I suppose that what they are calling the "force of free fall" is the weight, M g.
Frictional work performed against air resistance while falling will then be
0.022 M g H
Subtract that from M g H to get the kinetic energy when it hits the water.
(1/2) M V^2 = 0.978 M g H
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