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March 29, 2015

March 29, 2015

Posted by **shay** on Monday, February 7, 2011 at 12:15pm.

- physics -
**drwls**, Monday, February 7, 2011 at 4:20pmI suppose that what they are calling the "force of free fall" is the weight, M g.

Frictional work performed against air resistance while falling will then be

0.022 M g H

Subtract that from M g H to get the kinetic energy when it hits the water.

(1/2) M V^2 = 0.978 M g H

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