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March 28, 2017

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Air rushing over the wings of high-performance race cars generates unwanted horizontal air resistance but also causes a vertical downforce, which helps cars hug the track more securely. The coefficient of static friction between the track and the tires of a 552-kg car is 0.967. What is the magnitude of the maximum acceleration at which the car can speed up without its tires slipping when a 3150-N downforce and an 1300-N horizontal air resistance force act on it?

  • PHYSICS!! - ,

    We need the horizontal acceleration so,
    ax=Fx/m

    Since Fx, or the horizontal forces acting on the car is composed of the air resistance and the force of static friction,
    ax=(fs-1300N)/m

    Looking for fs(static friction):
    fs=us*N

    N=mg+3150N
    =(552kg)(9.8)+3150N
    =8559.6N

    fs=(0.967)(8559.6N)
    =8277.13N

    Solving for ax:
    ax=(8277.13-1300N)/553
    ax=12.54m/s2

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