Posted by **Veronika** on Monday, February 7, 2011 at 7:54am.

An electron moves at a speed of 6.0 x 10^-6 perpendicular to a constant magnetic field. The path is a circle of radius 1.3 x 10^-3m.

What is the magnitude of the field.

Find the magnitude of the electron acceleration.

- Physics -
**drwls**, Monday, February 7, 2011 at 10:07am
centripetal force = magnetic force

m V^2/R = e V B, so

B = (m/e)*(V/R)

m and e are the electron mass and charge

electron acceleration = V^2/R

- Physics -
**drwls**, Monday, February 7, 2011 at 10:09am
You forgot to include the units for speed. 6*10^-6 is very slow if you are talking about m/s. Are you sure you gor the exponent right?

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