Posted by Veronika on Monday, February 7, 2011 at 7:54am.
An electron moves at a speed of 6.0 x 10^6 perpendicular to a constant magnetic field. The path is a circle of radius 1.3 x 10^3m.
What is the magnitude of the field.
Find the magnitude of the electron acceleration.

Physics  drwls, Monday, February 7, 2011 at 10:07am
centripetal force = magnetic force
m V^2/R = e V B, so
B = (m/e)*(V/R)
m and e are the electron mass and charge
electron acceleration = V^2/R

Physics  drwls, Monday, February 7, 2011 at 10:09am
You forgot to include the units for speed. 6*10^6 is very slow if you are talking about m/s. Are you sure you gor the exponent right?
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