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March 1, 2015

March 1, 2015

Posted by **patrick** on Monday, February 7, 2011 at 1:19am.

- maths -
**drwls**, Monday, February 7, 2011 at 6:17amy = x^2 = sqrt(8x)

x^4 = 8x

(x^3 - 8)*x = 0

x = 0 or 2

For the area between the curves, integrate

(8x)^(1/2) - x^2

from 0 to 2.

sqrt8*2^(3/2)/(3/2) - (2^3)/3

= 16/3 - 8/3 = 8/3

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