Posted by **Erica** on Monday, February 7, 2011 at 1:11am.

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the y-axis.

y = cube rt. (x) + 2

Thank you so much!!

- Calc -
**helper**, Monday, February 7, 2011 at 1:22am
You need parentheses.

Is your problem,

y = (cubert(x)) + 2

y = (cubert(x + 2))

- Calc -
**helper**, Monday, February 7, 2011 at 1:25am
I hit post, just as I realized what you meant. Sorry.

Since the parentheses are around the (x),

you most likely mean,

y = (cubert(x)) + 2.

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