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Posted by on Monday, February 7, 2011 at 1:11am.

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the y-axis.

y = cube rt. (x) + 2

Thank you so much!!

  • Calc - , Monday, February 7, 2011 at 1:22am

    You need parentheses.

    Is your problem,
    y = (cubert(x)) + 2
    y = (cubert(x + 2))

  • Calc - , Monday, February 7, 2011 at 1:25am

    I hit post, just as I realized what you meant. Sorry.

    Since the parentheses are around the (x),
    you most likely mean,
    y = (cubert(x)) + 2.

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