Posted by Jon on Monday, February 7, 2011 at 12:28am.
The final temperature of the 200 g of water will be the same as that of the 100g of hot water that was added. That is when thermal equilibrium exists.
At the final temperature T, the heat gained by the initially cold water will equal the heat lost by the hot water.
C*200g*(T-20) = C*100g*(80-T)
The specific heat C cancels out.
Solve for T, the final equilibrium temperature
2(T-20) = 80-T
3T = 120
T = 40 C
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