Posted by Michaela on Sunday, February 6, 2011 at 8:01pm.
Factor these:
8x^3125
81x^625
18x^3+63x^250x175
x^411x^2+18
I'm so lost!

algebra  bobpursley, Sunday, February 6, 2011 at 8:20pm
differece of cubes
differece of cubes
9x^2(2x+7)25(2x+7) then gather the common factor, to (2x+7)(9x^225), and now the second term is a differece of squares, so It can be factored.
Last
(x^29)(x^22) both of these terms are difference of squares. (last term (xsqrt2)(x+sqrt2)