Homework Help: Chemistry

Posted by Melissa on Sunday, February 6, 2011 at 7:18pm.

A 23.0mL sample of a diprotic acid is titrated with 0.260M KOH. If 55.5mL of base is required to reach the second equivalence point, what is the concentration of the acid? I'm not sure how to do this.

Chemistry - DrBob222, Sunday, February 6, 2011 at 11:31pm
H2A + KOH ==> KHA + H2O
KHA + KOH ==> K2A + H2O

If 55.5 mL KOH were required to titrate to the second equivalence, then 55.5/2 mL were required to reach the first equivalence point.
(55.5/2)*0.260 = ?? mmoles KOH.
mmoles H2A = the same.

M H2A = mmoles/mL
You know mmoles H2A and mL H2A, solve for M
Chemistry - Anuar, Saturday, April 30, 2011 at 4:32pm
7.2
Chemistry - Anuar, Saturday, April 30, 2011 at 4:32pm
7.2

Answer this Question

Related Questions

chemistry - a 30.0ml sample of diprotic acid is titrated with .260M KOH. if 68....
chemistry - A 20ml sample of .125M diprotic acid solution was titrated with ....
Chemistry - A 40.00 mL sample of 0.1 M NH3 is titrated with 0.150 M HCl solution...
Chemistry - When a diprotic acid, H2A, is titrated by NaOH, the protons on the ...
chemistry - Consider a 20.0mL sample of 0.105M HC2H3O2 is titrated with 0.125M ...
chemistry - 0.5 L of a 0.30 M HCl solution is titrated with a solution of 0.6 M ...
Chemistry - In this case, the inflection point, and equivalence, occurs after 23...
Chemistry - A 50.0 mL sample of 0.23 M propanoic acid, CH3CH2COOH, a weak ...
chemistry - A volume of 100mL of a 0.800 M HNO3 solution is titrated with 0.640 ...
Chemistry - A titration is performed by adding .600 M KOH to 40.0 mL of .800 M ...

For Further Reading

First Name:
School Subject:
Answer: