Posted by liz on Sunday, February 6, 2011 at 4:43pm.
Have you tried to balance the equation?
That would be a good place to start.
You will need twice as many CO2's as C2H5OH's. That should be obvious.
You will need 1/3 as many H2O's as C2H5OH's.
So start with
C2H5OH +xO2 -> 2CO2 + 3 H2O
Now all you need to do is balance the O's to figure out what x is.
C2H508+x02_>2C02+3H2=X=23 DUMB***
we start with:
C2H5OH + O2-> CO2 + H2O
Think of this as our skeleton. It cannot be changed. Then, list how many there are of each element. This would be how it would look like:
C: 2 C: 1
H:6 H: 2
O: 3 O: 3
Now, always do hydrogen and oxygen last, so we have to do C first. To make the second carbon have 2, simply put 2 in front of CO2. This changes the O on the right to 5. Now that we have the C's equal, we can balance H. We do this by placing a 3 before the H2O. Now we have this:
C2H5OH + O2-> 2CO2 + 3H2O
C: 2 C: 2
H:6 H: 6
O: 3 O: 7
Now to find the number to put before O2... It is 3...
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