Posted by Tracy on Sunday, February 6, 2011 at 2:52pm.
A building contractor is planning to build an apartment complex with one, two or three bedroom apartments. Let x,y,z respectively denote the number of apartments of each type to be built. Suppose that the builder will spend a total of $8,277,000, and that the costs for the three types of apartments are $25,000, $35,000, and $54,000 respectively. Then the 'cost equation' for the builder is:
?x + ?y + 54 z =?
Suppose he plans to build a total of 236 apartments, then complete the equation in x, y, and z which describes this:
?x + ?y + z =?
Further suppose that the number of one bedroom apartments must equal the total number of bigger apartments. Then we get the restriction:
x +(?)y +(?)z = 0.
Finally, find the solution to these equations: x =?, y =?, and z =?

New age Math  bobpursley, Sunday, February 6, 2011 at 3:19pm
New age? this has been standard fare for a hundred years, and millions before you have figured it out. The subject my generation suffered through was candy mixtures.
25x+35y+54z=8277000
x+y+z=236
x+yz=0 (in the sentence, it was stated that x=y+z)
have fun, I am not going to do the solution for you.
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