Posted by Tracy on Sunday, February 6, 2011 at 10:32am.
A building contractor is planning to build an apartment complex with one, two or three bedroom apartments. Let x,y,z respectively denote the number of apartments of each type to be built. Suppose that the builder will spend a total of $8,277,000, and that the costs for the three types of apartments are $25,000, $35,000, and $54,000 respectively. Then the 'cost equation' for the builder is:
?x + ?y + 54 z =?
Suppose he plans to build a total of 236 apartments, then complete the equation in x, y, and z which describes this:
x +(?)y +(?)z = 0.
Finally, find the solution to these equations: x =?, y =?, and z =?

New Age Math  helper, Sunday, February 6, 2011 at 12:02pm
The two equations, based on your fillintheblanks above are,
25x + 35y + 54z = 8277
x + y + z = 236
Are you sure this is the exact problem as written?
Are far as I know, this problem cannot be solved to get an exact number for x, y and z .
To solve simultaneous equations in three unknown requires three equations (I've been taught).
If this can be solved with only two equations it is beyond my scope of my knowledge regarding simultaneous equations.
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