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September 18, 2014

September 18, 2014

Posted by **Jim** on Sunday, February 6, 2011 at 3:07am.

- Algebra -
**jai**, Sunday, February 6, 2011 at 5:40amrecall:

speed (v) is distance (d) travelled over a certain period of time (t), or

v = d/t

since Suzi is faster that Jim given their speeds, we can get the difference of their speeds:

69 - 41 = 28 mph

*this 28 mph only means that after 1 hour, the gap or distance between them is 28 miles, since v = d/t --> 28 = d/1 --> d = 28)

in the problem, it's said that the distance between them when Suzi arrived home is 112,, therefore:

v = d/t

28 = 112/t

t = 4 hours

since they left at the same time, Suzi drove for 4 hours, therefore:

v = d/t

69 = d/4

d = ?

now solve for d.

hope this helps~ :)

- Algebra -
**helper**, Sunday, February 6, 2011 at 9:26amD = RT, T = D/R

69 = Suzi Rate

T = Suzi Time

69T = Suzi Distance

41 = Jim Rate

T + 2.73 = Jim Time (T = 112/41 = 2.73)

41(T + 2.73) = Jim Distance

Since distances are equal

69T = 41(T + 2.73)

69T = 41T + 111.93

28T = 111.93

T = 3.99 = 4

69T = Suzi Distance

69(4) = 276 miles

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