Posted by Jim on Sunday, February 6, 2011 at 3:07am.
recall:
speed (v) is distance (d) travelled over a certain period of time (t), or
v = d/t
since Suzi is faster that Jim given their speeds, we can get the difference of their speeds:
69 - 41 = 28 mph
*this 28 mph only means that after 1 hour, the gap or distance between them is 28 miles, since v = d/t --> 28 = d/1 --> d = 28)
in the problem, it's said that the distance between them when Suzi arrived home is 112,, therefore:
v = d/t
28 = 112/t
t = 4 hours
since they left at the same time, Suzi drove for 4 hours, therefore:
v = d/t
69 = d/4
d = ?
now solve for d.
hope this helps~ :)
D = RT, T = D/R
69 = Suzi Rate
T = Suzi Time
69T = Suzi Distance
41 = Jim Rate
T + 2.73 = Jim Time (T = 112/41 = 2.73)
41(T + 2.73) = Jim Distance
Since distances are equal
69T = 41(T + 2.73)
69T = 41T + 111.93
28T = 111.93
T = 3.99 = 4
69T = Suzi Distance
69(4) = 276 miles
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