Posted by **Dave** on Saturday, February 5, 2011 at 11:14pm.

Find the speed of a pendulum bob at the bottom of its swing if its initial displacement is 5 degrees and its period is 2 s.

- Physics -
**drwls**, Sunday, February 6, 2011 at 2:15am
The speed at the bottom of the swing is the maximum value. It is equal to (linear amplitude)*(angular velocity)

= Vmax = L*sin5*(2*pi*f)

You are going to need the length of the pendulum, L, to get the amplitude.

f = 0.5 Hz = (1/(2 pi))*sqrt(g/L)

sqrt(g/L) = 3.14

g/L = 9.86 s^-1

L = 0.994 m

Vmax = 0.27 m/s

- Physics -
**Dave**, Sunday, February 6, 2011 at 3:12am
Thanks, I couldn't find an equation that derives the max velocity of the pendulum in my textbook.

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