A Jet has a liftoff speed of 160 km/hr. What minimum uniform acceleration does this require if the aircraft is to be airborne after a takeoff run of 300m?

change the km/hr to m/s.

Vf^2=2*a*distance.

To find the minimum uniform acceleration required for the jet to be airborne after a takeoff run of 300m, we can use the following equation:

v^2 = u^2 + 2as

Where:
v = final velocity (0 km/hr because the jet needs to be airborne)
u = initial velocity (160 km/hr)
a = acceleration
s = displacement (300m, which needs to be converted to km)

First, let's convert the displacement from meters to kilometers:
300m = 300/1000 = 0.3 km

Now we can substitute the values into the equation and solve for acceleration (a):

0^2 = (160^2) + 2a(0.3)

0 = 25600 + 0.6a

0.6a = -25600

a = -25600/0.6

a ≈ -42667 km/hr^2

Since acceleration cannot be a negative value for this problem, we can ignore the negative sign. Therefore, the minimum uniform acceleration required for the jet to be airborne after a takeoff run of 300m is approximately 42667 km/hr^2.