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A spy satellite is in circular orbit around Earth. It makes one revolution in 5.95 hours. (Radius of the Earth=6.371 106 m)

(a) How high above Earth's surface is the satellite?
(b) What is the satellite's acceleration?

  • Physics -


    but velocity can be found..


    or v=sqrt (9.8 (re^2/(re+h))

    then put that v into the first equation, and solve for h.

    This is a form of Keplers' law.

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