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Physics

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A spy satellite is in circular orbit around Earth. It makes one revolution in 5.95 hours. (Radius of the Earth=6.371 106 m)

(a) How high above Earth's surface is the satellite?
(b) What is the satellite's acceleration?

  • Physics - ,

    velocity=2PI*(re+h)/period

    but velocity can be found..

    9.8(re/(re+h))^2=v^2/(re+h)

    or v=sqrt (9.8 (re^2/(re+h))

    then put that v into the first equation, and solve for h.

    This is a form of Keplers' law.

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