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November 28, 2014

November 28, 2014

Posted by **Hannah** on Saturday, February 5, 2011 at 11:46am.

p(x)= 3x^2 - 5x + 2

First I plugged 5 into the equation and got 52. Then I took the derivative which is 6x -5 and plugged in 5 and got 25. 52 - 25 = 27. Is this correct?

- Math(Please check) -
**helper**, Saturday, February 5, 2011 at 12:48pmNo, you are not correct. But, you almost had it!

To compute the actual increase in profit, first plug in 5, then plug in 6. The difference between f(5) and f(6) is the actual.

p(x)= 3x^2 - 5x + 2

p(5) = 3(5)^2 - 5(5) + 2 = 52

p(6) = 3(6)^2 - 5(6) + 2 = 80

p(6) - p(5) = 80 - 52 = 28

To compute the marginal profit

dp/dx = 6x - 5

6(5) - 5 = 25

Actual - marginal = 28 - 25 = 3

Check my math

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