Posted by **Hannah** on Saturday, February 5, 2011 at 11:37am.

Find the slope of the graph at

y=sqrt 2x^2 +1 at the point (2,3).

First I plugged 2 into the equation and got 3. Then the derivative of the equation is 4x and then I multiplied that by 3 and got 12. Is this correct?

- Math(Please check) -
**helper**, Saturday, February 5, 2011 at 1:02pm
y=sqrt 2x^2 +1 at the point (2,3).

No, you are not correct.

First, you need to find the derivative of,

(sqrt(2x^2 + 1))

dy/dx = 2x(2x^2 + 1)^(-1/2)

This is the slope of the tangent line at P.

Now plug in P(2,3)

2x(2x^2 + 1)^(-1/2)

2(2)(2(2^2) + 1)^(-1/2)

4(8 + 1)^(-1/2)

4 * (9)^(-1/2) = 4 * 1/(9^(1/2))= 4/3

## Answer This Question

## Related Questions

- MATH - I need to simply this equation, but I got stuck. h/(4-sqrt(16+h)) = y ...
- math - Find the equation of the tangent line to the graph of f(x) = 2x − 6...
- Calculus derivative - find the slope m and an equation of the tangent line to ...
- Variation-Questions - I have some questions that I don't understand and need to ...
- Math (Calculus 121) - The derivative tells you the slope at any point. df/dx = 8...
- Please check my Calculus - 1. Which of the following describes the behavior of f...
- math-Inverse functions - f(x)=-4x-2 & g(x)=5x-6. Find (f*g) and state domain. f(...
- Math(Please check) - What is the difference between the actual increase in ...
- math - i have more than one question so if u no any of the answers please tell ...
- Calculus again - Find the equation of the tangent to y=2-xe^x at the point where...

More Related Questions