Sunday

April 19, 2015

April 19, 2015

Posted by **anonymous** on Saturday, February 5, 2011 at 3:21am.

2^(9x-7)=7

My first step was to change it to

log(base 2) 7 = 9x-7

i got 1.0897

Did i do something wrong or did i miss one question?

- pre calculus -
**Reiny**, Saturday, February 5, 2011 at 7:02amjust take log of both sides

log (2^(9x-7)) = log 7

(9x-7) log2 = log7

9x - 7 = log7/log2

etc.

your answer is correct, see

http://www.google.ca/search?hl=en&source=hp&q=%28%28log%287%29%2Flog%282%29%2B7%29%2F9&btnG=Google+Search&aq=f&aqi=&aql=&oq=

- pre calculus -
**drwls**, Saturday, February 5, 2011 at 7:03am[9x -7] log 2 = log 7

Any log base can be used, as long as it is the same for both sides.

9x - 7 = 2.807

9x = 9.807

x = 1.0897

Your answer is correct!

pre-calculus - solve the following logarithmic equation. be sure to reject any ...

Pre-Calculus - Find a solution to the equation if possible. Give the answer in ...

Logs. - Can you please help me with the following log. problems? thanxs! Solve ...

Math - Find the exact solution, using common logarithms, and a two-decimal-place...

precalc/trig - Solve the Logarithmic equation algebraically. Give an Exact ...

Advanced Functions/ Precalculus Log - 1. Evaluate 4^(log base4 64) + 10^(log100...

Math 117 - Give exact and approximate solutions to three decimal places. (x-8)^2...

calculus - solve the following exponential equation. 8^x=3 what is the exact ...

Pre-Calculus - Laws of Logarithms Without using a calculator use the change of ...

Precalculus - Solve (log x)^2 = log x Also, when will their be a possibility ...