Posted by Anonymous on Friday, February 4, 2011 at 4:03pm.
At a temperature of 20°C, the volume V (in liters) of 1.33 g of O2 is related to its pressure p (in atmospheres) by the formula
V(p) = 1/p
(a) What is the average rate of change of V with respect to p as p increases from p = 7 to p = 8?
L/atm
(b) What is the rate of change to V with respect to p when p = 7?
L/atm

Math  Zachary, Monday, September 23, 2013 at 6:10pm
I don't know

Math  Tee, Sunday, December 1, 2013 at 9:11am
V(p) = 1/p
V(6) = 1/6
V(7) = 1/7
ΔV = V(7)  V(6) = 1/7  1/6 = 1/42
Δp = 7  6 = 1
a)Average rate of change:
ΔV/Δp = (1/42)/1 = 1/42 Liter/atmosphere

Math  Tee, Sunday, December 1, 2013 at 9:12am
V(p) = 1/p
V(6) = 1/6
V(7) = 1/7
ΔV = V(7)  V(6) = 1/7  1/6 = 1/42
Δp = 7  6 = 1
a)Average rate of change:
ΔV/Δp = (1/42)/1 = 1/42 Liter/atmosphere
Actual rate of change
dV/dp = 1/p²
At p = 6
dV/dp = 1/6² = 1/36 L/atm
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