Posted by **Anonymous** on Friday, February 4, 2011 at 4:03pm.

At a temperature of 20°C, the volume V (in liters) of 1.33 g of O2 is related to its pressure p (in atmospheres) by the formula

V(p) = 1/p

(a) What is the average rate of change of V with respect to p as p increases from p = 7 to p = 8?

L/atm

(b) What is the rate of change to V with respect to p when p = 7?

L/atm

- Math -
**Zachary**, Monday, September 23, 2013 at 6:10pm
I dont know

- Math -
**Tee**, Sunday, December 1, 2013 at 9:11am
V(p) = 1/p

V(6) = 1/6

V(7) = 1/7

ΔV = V(7) - V(6) = 1/7 - 1/6 = -1/42

Δp = 7 - 6 = 1

a)Average rate of change:

ΔV/Δp = (-1/42)/1 = -1/42 Liter/atmosphere

- Math -
**Tee**, Sunday, December 1, 2013 at 9:12am
V(p) = 1/p

V(6) = 1/6

V(7) = 1/7

ΔV = V(7) - V(6) = 1/7 - 1/6 = -1/42

Δp = 7 - 6 = 1

a)Average rate of change:

ΔV/Δp = (-1/42)/1 = -1/42 Liter/atmosphere

Actual rate of change

dV/dp = -1/p²

At p = 6

dV/dp = -1/6² = -1/36 L/atm

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