Posted by Anonymous on Friday, February 4, 2011 at 12:38pm.
Let f be defined as follows.
y = f(x) = x^2  4 x
(a) Find the average rate of change of y with respect to x in the following intervals.
from x = 5 to x = 6
from x = 5 to x = 5.5
from x = 5 to x = 5.1
(b) Find the (instantaneous) rate of change of y at x = 5.
4

math  MathMate, Friday, February 4, 2011 at 3:11pm
(a)
Average rate of change of f(x) on an interval I = [x1,x2] equals (f(x2)f(x1))/(x2x1) where x2≠x1.
So if f(x)=x^2  4 x,
average rate of change between 5 and 6
= (f(6)f(5))/(62)
= (125)/(65)
= 7
(b)
Instantaneous rate of change at x=5
=f'(5)
where
f'(x)=2x4
so
f'(5)=104=6
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