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Posted by on Friday, February 4, 2011 at 4:38am.

A runner with mass 100 kg jogs around a circular track with circumference 1 km. If he
does one lap in 6 min, what is his angular momentum about the center of the track?

  • Physics - , Friday, February 4, 2011 at 6:22am

    In this case,
    Angular Momentum = M*V*R

    R = 1000 m/(2 pi) = 159.2 m
    V = 1000 m/(360 s) = 2.778 m/s

    Now do the MVR multiplication

  • Physics - , Thursday, February 17, 2011 at 5:42am

    44000kg

  • Physics - , Thursday, February 17, 2011 at 5:43am

    Theradiusofthetrackis R= C =1000m=160m.Thespeedoftherunneris 2π 2π
    v = d = 1000m = 2.78 ms . The angular momentum about the center is thus t 360s
    L = mvR = (100kg)(2.78 m )(160m) = 44000 Js or 44000 kg m2 . ss

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