Posted by **Angular Momentum** on Friday, February 4, 2011 at 4:38am.

A runner with mass 100 kg jogs around a circular track with circumference 1 km. If he

does one lap in 6 min, what is his angular momentum about the center of the track?

- Physics -
**drwls**, Friday, February 4, 2011 at 6:22am
In this case,

Angular Momentum = M*V*R

R = 1000 m/(2 pi) = 159.2 m

V = 1000 m/(360 s) = 2.778 m/s

Now do the MVR multiplication

- Physics -
**john**, Thursday, February 17, 2011 at 5:42am
44000kg

- Physics -
**john**, Thursday, February 17, 2011 at 5:43am
Theradiusofthetrackis R= C =1000m=160m.Thespeedoftherunneris 2π 2π

v = d = 1000m = 2.78 ms . The angular momentum about the center is thus t 360s

L = mvR = (100kg)(2.78 m )(160m) = 44000 Js or 44000 kg m2 . ss

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