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July 29, 2014

July 29, 2014

Posted by **Tyler** on Thursday, February 3, 2011 at 11:22pm.

f(x) = 4x2 - 5x

(a) Find f '(2).

(b) Use the answer in part (a) to find an equation of the tangent line to the parabola y = 4x2 - 5x at the point (2, 6).

y =

- calculus -
**Damon**, Thursday, February 3, 2011 at 11:47pmy = 4 x^2 - 5 x

y' = 8 x - 5

at x = 2

y'(2) = 16-5 = 11

m = 2

y = m x + b

6 = 2 (2) + b

b = 2

so

y = 2 x + 2

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