Saturday

March 28, 2015

March 28, 2015

Posted by **katrina** on Thursday, February 3, 2011 at 10:21pm.

Find the area of the triangle ABC:

- math -
**Henry**, Saturday, February 5, 2011 at 8:49pmA(2, 2), B(4, 6), C(10, -2).

(AB)^2 = (4 -2)^2 + (6 -2 )^2,

(AB)^2 = = 4 + 16 = 20.

AB=sqrt20 = sqrt(4*5) = 2*sqrt5 = 4.47.

(BC)^2 = (10 -4)^2 + (-2 -6)^2,

(BC)^2 = 36 + 64 = 100,

BC = sqrt100 = 10.

(AC)^2 = (10 -2)^2 + (-2 -2)^2,

(AC)^2 = 64 + 16 = 80,

AC=sqrt80 = sqrt(16*5) = 4*sqrt5=8.94.

A = AC * AB / 2,

A=4sqrt5 * 2sqrt5/2 = 8 * 5 / 2=20.

**Answer this Question**

**Related Questions**

Geometry - Please answer at least one . PLEASE 1. Triangle XYZ has a right ...

help math - In triangle ABC, points D,E,F are on sides BC,CA,AB respectively ...

Math - In triangle ABC, points D,E,F are on sides BC,CA,AB respectively such ...

HELP!!!!RIGHT NOW!!!! - Which set of side lengths shows similar triangles? (1 ...

heeeeeeeeeeeeeeeeeeeelp maths - In triangle ABC, points D,E,F are on sides BC,CA...

math - Let P and Q be the points on the sides AB and BC of a triangle ABC ...

construct a triangle - How can I construct a triangle ABC with vertices A(-4,2...

Math(Geometry) - In the diagram below(no diagram but details will be provided), ...

Math - The coordinates of the vertices of triangle ABC are A (-5,1), B (-2,3) ...

math - i have a question in math (( distance between two points )) the vertices ...