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December 20, 2014

December 20, 2014

Posted by **katrina** on Thursday, February 3, 2011 at 10:21pm.

Find the area of the triangle ABC:

- math -
**Henry**, Saturday, February 5, 2011 at 8:49pmA(2, 2), B(4, 6), C(10, -2).

(AB)^2 = (4 -2)^2 + (6 -2 )^2,

(AB)^2 = = 4 + 16 = 20.

AB=sqrt20 = sqrt(4*5) = 2*sqrt5 = 4.47.

(BC)^2 = (10 -4)^2 + (-2 -6)^2,

(BC)^2 = 36 + 64 = 100,

BC = sqrt100 = 10.

(AC)^2 = (10 -2)^2 + (-2 -2)^2,

(AC)^2 = 64 + 16 = 80,

AC=sqrt80 = sqrt(16*5) = 4*sqrt5=8.94.

A = AC * AB / 2,

A=4sqrt5 * 2sqrt5/2 = 8 * 5 / 2=20.

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