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April 21, 2014

April 21, 2014

Posted by **Anna** on Thursday, February 3, 2011 at 10:12pm.

- Calculus -
**MathMate**, Friday, February 4, 2011 at 12:41amf(x)=xe^x,

f'(x)=e^x+xe^x=(x+1)e^x

For the tangent to have a slope of 1/2, equate

f'(x)=1/2 and solve for x:

(x+1)e^x=0.5

Solve by trial and error to be -0.315±

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