Posted by Scott on .
A bullet with a mass of mb= 0.05 kg is speeding toward a block of mass m= 10kg. The bullet is moving at vb= 200m/s and the block is at rest. the bullet collides with he block and knocks the block over the edge. the edge is a height h= 0.5m above ground. how far from he edge does the block ( with the bullet inside) land?
Neglect friction. Otherwise you would need to know the value of the friction coefficient and how far it slides to reach the edge.
Apply conservation of momentum to get the velocity Vo of the block after the bullet is embedded inside.
Multiply Vo by the time it takes to fall H = 0.5 m,. That will give you the answer.
T = sqrt(2H/g)