posted by John on .
A)a 72 kg man jumps from a window 1.2 m above a sidewalk. the acceleration of gravity is 9.81 m/s2. what is his speed just before his feet strike the pavement? answer in units of m/s
B) if the man jumps with his knees and ankles locked, the only cushion for his fall is approximately .48 cm in the pads of his feet. calculate the magnitude of the average force exerted on him by the ground in this situation. answer in units of N.
A) V = sqrt(2 g H)
B) (1/2)MV^2 = Force*("cushion distance")