Posted by **Sam** on Thursday, February 3, 2011 at 6:55pm.

Cost,Revenue,and Profit: Estimate the number of scanners that would produce a maximum profit when p is the price per scanner and x is the number of scanners. p= 100-0.0001x and the cost for producing x scanners is C= 350,000+30x and the profit for producing and selling x scanners is P=R-C=xp-C. SOmehow I got P=-0.0001x^2+70x-350000. Can you verify that? I tried graphing it to get the number of scanners for the maximum profit, but my calculator doesn't work. Is there another way to find the maximum number of scanners?

## Answer This Question

## Related Questions

- algebra - A marketing department estimates that demand for a product is given by...
- Pre-Calculus - P= -0.0001x^2+70x-350000 By graphing this what would be the ...
- calculus - A lamp has a cost function of C(x) = 2500 + 10x, where x is the ...
- math - The weekly marginal cost functions C'(x) and the weekly marginal revenue ...
- Math 11u - A Computer company has been selling 1200 computer games per week at $...
- Microeconomics - The following table indicates the prices various buyers are ...
- Calculus Help - using the cost function C(q) = q3−60q2+1200q+760 for 0 &#...
- college/microeconomics - The following table indicates the prices various buyers...
- Calculus - the cost function C(q) = q3−57q2+1083q+1010 for 0 ≤ q &#...
- maths - A clothing firm determines that in order to sell x suits, the price per ...

More Related Questions