Posted by alexa on Thursday, February 3, 2011 at 5:07pm.
john's paint crew knows from experience that its 18 ft ladder is particularly stable when the distance from the ground to the top of the ladder is 5 ft more than the distance from the building to the base of the ladder. in this position, how far up the building does the ladder reach?

functions  helper, Thursday, February 3, 2011 at 5:36pm
Functions?
This is a geometry problem.
The ladder up against the wall forms a right triangle.
x = base
x + 5 = opposite side
18 = hypotenuse
Using the Pythagorean theorem,
x^2 + (5 + x)^2 = 18^2
Solve for x
5 + x = how far up the blding the ladder reaches.

functions  Reiny, Thursday, February 3, 2011 at 5:37pm
let the base be x ft
then the height is x+5 ft
solve x^2 + (x+5)^2 = 18^2

functions  Anonymous, Wednesday, September 4, 2013 at 3:03pm
14.98?

functions  Mighty, Thursday, October 10, 2013 at 10:27pm
x = 9.989983874
Use that answer to check your work.
(9.979983874)^2 + (9.979983874 + 5)^2 = 18^2
The height is exactly 14.979983874 ft.
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