Posted by **alexa** on Thursday, February 3, 2011 at 5:07pm.

john's paint crew knows from experience that its 18 ft ladder is particularly stable when the distance from the ground to the top of the ladder is 5 ft more than the distance from the building to the base of the ladder. in this position, how far up the building does the ladder reach?

- functions -
**helper**, Thursday, February 3, 2011 at 5:36pm
Functions?

This is a geometry problem.

The ladder up against the wall forms a right triangle.

x = base

x + 5 = opposite side

18 = hypotenuse

Using the Pythagorean theorem,

x^2 + (5 + x)^2 = 18^2

Solve for x

5 + x = how far up the blding the ladder reaches.

- functions -
**Reiny**, Thursday, February 3, 2011 at 5:37pm
let the base be x ft

then the height is x+5 ft

solve x^2 + (x+5)^2 = 18^2

- functions -
**Anonymous**, Wednesday, September 4, 2013 at 3:03pm
14.98?

- functions -
**Mighty**, Thursday, October 10, 2013 at 10:27pm
x = 9.989983874

Use that answer to check your work.

(9.979983874)^2 + (9.979983874 + 5)^2 = 18^2

The height is exactly 14.979983874 ft.

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