One side of a rectangle is 12 inches, and the other side is x inches.What values of x will make the perimeter at most 44 inches?

P = 2L + 2W

44>= 2(12) + 2x
44 >= 24 + 2x
20 >= 2x
10 <= x

Well, if we let the length of one side be 12 inches, and the other side be x inches, then the perimeter is given by P = 2(12 + x).

To find the values of x that make the perimeter at most 44 inches, we can set up the inequality:

2(12 + x) ≤ 44

Now let's solve for x:
12 + x ≤ 22

Subtracting 12 from both sides, we get:
x ≤ 10

So any value of x that is less than or equal to 10 inches will make the perimeter at most 44 inches.

And that's the "inch-resting" solution!

To find the perimeter of a rectangle, you add the lengths of all four sides together.

Let's denote the length of one side as 12 inches, and the other side as x inches.

The formula for the perimeter of a rectangle is: Perimeter = 2(length + width)

Given that one side is 12 inches, the perimeter in terms of x inches can be expressed as: Perimeter = 2(12 + x)

We want the perimeter to be at most 44 inches. Therefore, the inequality would be: 2(12 + x) ≤ 44

To solve the inequality, follow these steps:

Step 1: Distribute the 2 to both terms inside the parentheses: 24 + 2x ≤ 44

Step 2: Subtract 24 from both sides of the inequality: 2x ≤ 44 - 24

Simplified Step 2: 2x ≤ 20

Step 3: Divide both sides of the inequality by 2: x ≤ 10

Therefore, the values of x that will make the perimeter at most 44 inches are x ≤ 10.

To find the values of x that will make the perimeter of the rectangle at most 44 inches, we need to use the formula for the perimeter of a rectangle, which is given by:

Perimeter = 2 * (Length + Width)

In this case, we know that one side (Length) of the rectangle is 12 inches, and the other side (Width) is x inches. So we can substitute these values into the formula and solve for x.

Perimeter = 2 * (12 + x)

Now we set up the inequality for the maximum perimeter:

2 * (12 + x) ≤ 44

To solve this inequality, we will follow the steps below:

1. Distribute the 2 to both terms inside the parentheses:

24 + 2x ≤ 44

2. Subtract 24 from both sides of the inequality:

2x ≤ 44 - 24
2x ≤ 20

3. Divide both sides by 2 to isolate x:

x ≤ 20/2
x ≤ 10

Therefore, the values of x that will make the perimeter at most 44 inches are x ≤ 10. In other words, x can be any value less than or equal to 10 inches.