Hydrogen gas has been suggested as a clean fuel because it produces only water vapor when it burns. If the reaction has a 95.4% yield, What mass of hydrogen forms 94 Kg of water?
To find the mass of hydrogen that forms 94 kg of water, we need to use the stoichiometry of the reaction. The balanced chemical equation for the reaction of hydrogen gas (H2) burning to form water (H2O) is:
2H2 + O2 -> 2H2O
From this equation, we can see that for every 2 moles of hydrogen gas, we get 2 moles of water. This gives us a 1:1 ratio between the moles of hydrogen and water.
Step 1: Convert the mass of water into moles. We can use the molar mass of water (18.01528 g/mol) to do this.
Moles of water = Mass of water / Molar mass of water
Moles of water = 94,000 g / 18.01528 g/mol
Moles of water = 5218.28 mol
Step 2: Since the ratio of moles of hydrogen to water is 1:1, the moles of hydrogen in the reaction will be the same as the moles of water.
Moles of hydrogen = Moles of water
Moles of hydrogen = 5218.28 mol
Step 3: Calculate the mass of hydrogen using the moles of hydrogen and the molar mass of hydrogen (2.01588 g/mol).
Mass of hydrogen = Moles of hydrogen × Molar mass of hydrogen
Mass of hydrogen = 5218.28 mol × 2.01588 g/mol
Mass of hydrogen = 10,522.29 g
Step 4: Convert the mass of hydrogen from grams to kilograms.
Mass of hydrogen = 10,522.29 g = 10.52229 kg
Therefore, the mass of hydrogen that forms 94 kg of water, with a yield of 95.4%, is approximately 10.522 kg.