The area of a rectangle is 128 in².

If the length is twice the width,
what is the length of the rectangle?
A) 64 in.

B) 16 in.

C) 8 in.

D) 4 in.

The length of a swimming pool is 22 ft.
The width is 40 ft. If the volume of the pool is
2,500 ft³, which equation below could be used to
find the depth of the pool?
A) (22 + 40)x = 2500

B) 22 + 40 + x = 2500

C) 66x = 2500

D) 22 40 x = 2500

D) 22 40 x = 2500

for the Question,

The area of a rectangle is 128 in².
If the length is twice the width,
what is the length of the rectangle?
A) 64 in.

B) 16 in.

C) 8 in.

D) 4 in.

the answer is C
hope this helps! :)

I answered one for you. Now it's your turn. I'll be glad to check your answer.

oof i just realized this was years ago..... oh well :)!

byeee

To find the length of the rectangle, we can use the formula for the area of a rectangle which is A = length × width.

Given that the area is 128 in² and the length is twice the width, let's assume the width is "w" inches. Therefore, the length would be "2w" inches.

Substituting the values in the formula, we have:

128 = (2w) × w

128 = 2w²

Divide both sides by 2:

64 = w²

Taking the square root of both sides:

√64 = √(w²)

8 = w

So, the width of the rectangle is 8 inches and since the length is twice the width, the length would be 2 × 8 = 16 inches.

Therefore, the correct answer is B) 16 in.

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For the second question, to find the depth of the swimming pool, we can use the formula for volume which is V = length × width × depth.

Given that the length is 22 ft, the width is 40 ft, and the volume is 2,500 ft³, we need to find the equation that represents the depth of the pool.

Multiplying the length, width, and depth, we have:

2500 = 22 × 40 × depth

2500 = 880 × depth

Divide both sides by 880 to solve for the depth:

depth = 2500 / 880

depth ≈ 2.84 ft

Therefore, none of the provided options correspond to the correct equation for finding the depth of the pool.