An automobile with an initial speed of 3.56

m/s accelerates uniformly at the rate of 2.7
m/s2. Find the displacement of the car after 4.1s.

Have you never seen the equation

X = Vo*t + (a/2)t^2 ?

If not, learn it now.

Vo = initial velocity
t = elapsed time
a = acceleration rate
X = distance travelled

Turn the crank. Solve for X

To find the displacement of the car after 4.1 seconds, we can use the equation for displacement under uniform acceleration:

Displacement = Initial Velocity × Time + (1/2) × Acceleration × Time^2

Given:
Initial Velocity (u) = 3.56 m/s
Acceleration (a) = 2.7 m/s^2
Time (t) = 4.1 s

Plugging in these values into the formula, we get:

Displacement = (3.56 m/s) × (4.1 s) + (1/2) × (2.7 m/s^2) × (4.1 s)^2

Calculating further:

Displacement = (3.56 m/s) × (4.1 s) + (1/2) × (2.7 m/s^2) × (4.1 s)^2
= 14.596 m + 0.5 × 2.7 m/s^2 × 16.81 s^2
= 14.596 m + 0.5 × 2.7 m/s^2 × 16.81 s^2
= 14.596 m + 22.70805 m
= 37.30405 m

Therefore, the displacement of the car after 4.1 seconds is approximately 37.3 meters.