Homework Help: Physics

Posted by Marissa on Thursday, February 3, 2011 at 10:45am.

while on the moon, the Apollo astronauts enjoyed the effect of a gravity much smaller than that on earth. if Neil Armstrong jumped up on the moon with an initial speed of 1.51 m/s to a height of 0.700m, what amount of gravitational acceleration did he experience?

Physics - drwls, Thursday, February 3, 2011 at 11:22am
Using conservation of energy,
(1/2)M Vo^2 = M g'H, so
g' = Vo^2/(2H)
is the value of the acceleration of gravity on the moon.

I get 1.63 m/s^2
Physics - Marko, Monday, August 22, 2011 at 7:52am
2gh=v^2
2*0.7*g=1.51^2
1.4g=1.51^2 /g
1.4=2.2801g
g=1.4/2.2801
g=0.6140081575 m/s^2

1.63m/s^2 is not the correct answer, take for example this:

10=5g What is 'g'?
g=10/5=2
Physics - Tyandra, Thursday, October 20, 2011 at 6:00pm
1.63 m/s^2 is the correct answer
Physics - Matt, Sunday, December 4, 2011 at 11:28am
Marko 1.51^2 /g doesn't equal 2.2801g it equals 2.2801/g. So your answer is the reciprical of the right answer. Nice try though.

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