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October 20, 2014

October 20, 2014

Posted by **Eric** on Thursday, February 3, 2011 at 1:45am.

- math -
**Bosnian**, Thursday, February 3, 2011 at 2:19amIn en.wikipedia type: "Half-life"

and read text, and retype formulas.

So:

N(t)=N0*e^(-lambda*t)

N(t)=N(17)=3

N0=10

t=17

3=10*e^(-lambda*17) Divide with 10

3/10=e^(-lambda*17)

e^(-lambda*17)=3/10

-lambda*17=ln(3/10)Divide with 17

-lamba=ln(0.3)/17

lamda=-ln(0.3)/17

lamda=-(-1,203972804326)/17

lamda=1,203972804326/17

lamda=0,07082193

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