CaO(s) reacts with SO2(g) according to the following equations: CaO9(s)+So2(g)--> CaSO3(g).
A 8.85g mixture containing CaO(s) is placed in a 3.00-L container. The container is filled with SO2(g) to a pressure of 749 torr, at 20.0 degree Celsius. After the reaction has gone to completion, the pressure inside the flask is 390 torr, also at 20.0 degree Celsius. What is the mass of CaSO39(s) produced? Assume that only CaO(s) in the mixture reacts with SO2(g).
To find the mass of CaSO3(s) produced, we need to determine the amount of CaO(s) that reacted and then use stoichiometry to convert it to the mass of CaSO3(s).
Step 1: Calculate the initial moles of SO2(g)
Using the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
Given:
Pressure (P initial) = 749 torr
Volume (V) = 3.00 L
Temperature (T) = 20.0°C = 293.15 K
Convert torr to atm by dividing by 760:
P initial (atm) = 749 torr / 760 torr/atm = 0.985 atm
Using the ideal gas law, rearrange it to solve for moles:
n initial = (P initial * V) / (R * T)
Rearranging further,
n initial = (0.985 atm * 3.00 L) / (0.0821 L*atm/mol*K * 293.15 K)
Calculate n initial to find the moles of SO2 initial.
Step 2: Calculate the final moles of SO2(g)
Using the same procedure as Step 1, use the final pressure (P final) to find n final.
Given:
P final = 390 torr
T = 20.0°C = 293.15 K
Convert torr to atm:
P final (atm) = 390 torr / 760 torr/atm = 0.513 atm
Calculate n final to find the moles of SO2 final.
Step 3: Determine the moles of CaO(s) reacted
From the balanced equation, the stoichiometric ratio between CaO(s) and SO2(g) is 1:1. This means that for every mole of CaO(s) reacted, one mole of SO2(g) is consumed.
Since the moles of CaO(s) reacted is equal to the moles of SO2(g) reacted, we can use the moles of SO2 initial and final to determine the moles of CaO(s) reacted.
Moles of CaO(s) reacted = Moles of SO2(g) initial - Moles of SO2(g) final
Step 4: Convert moles of CaO(s) reacted to grams of CaO(s)
Use the molar mass of CaO to convert the moles to grams.
Given:
Molar mass of CaO = 56.08 g/mol
Mass of CaO(s) reacted = Moles of CaO(s) reacted * Molar mass of CaO
Step 5: Calculate the moles of CaSO3(s) produced
From the balanced equation, the stoichiometric ratio between CaO(s) and CaSO3(s) is 1:1. This means that one mole of CaO(s) reacts to produce one mole of CaSO3(s).
Since the moles of CaO(s) reacted is equal to the moles of CaSO3(s) produced, the moles of CaSO3(s) is equal to the moles of CaO(s) reacted.
Moles of CaSO3(s) produced = Moles of CaO(s) reacted
Step 6: Convert moles of CaSO3(s) produced to grams of CaSO3(s)
Use the molar mass of CaSO3 to convert the moles to grams.
Given:
Molar mass of CaSO3 = 120.10 g/mol
Mass of CaSO3(s) produced = Moles of CaSO3(s) produced * Molar mass of CaSO3
By following these steps, you can calculate the mass of CaSO3(s) produced.