Tuesday

January 27, 2015

January 27, 2015

Posted by **Rachal** on Wednesday, February 2, 2011 at 6:27pm.

The one-to-one function f is defined by f(x)=(4x-1)/(x+7).

Find f^-1, the inverse of f. Then, give the domain and range of f^-1 using interval notation.

f^-1(x)=

Domain (f^-1)=

Range (f^-1)=

Any help is greatly appreciated.

- Algebra -
**helper**, Wednesday, February 2, 2011 at 7:05pmf(x)=(4x-1)/(x+7)

y = (4x-1)/(x+7)

Rewrite as:

y = (4x)/(x+7)- 1/(x+7)

Multiply both sides by x+7:

(x + 7)y = 4x - 1

Expand out terms of the left hand side:

xy + 7y = 4x - 1

xy - 4x = -7y - 1

x(y - 4) = -7y - 1

Divide both sides by y - 4:

x = (-7y - 1)/(y - 4)

f^-1 = (-7x - 1)/(x - 4)

Can you do the domain and range now?

- Algebra -
**Rachal**, Wednesday, February 2, 2011 at 7:11pmI don't know if this is right but this is what I came up with.

f^-1=(-7x+1)/(x-4)

domain f(^-1)=(-inf,-7)U(-7,inf)

range f(^-1)=(-inf,4)U(4,inf)

Let me know if it looks right. Thanks

**Answer this Question**

**Related Questions**

Algebra-I'm still stuck - The one-to-one function f is defined by f(x)=(4x-1)/(x...

Algebra- is my answer right - The one-to-one function f is defined by f(x)=(4x-1...

Advanced Algebra - What is the inverse of each of the functions defined by the ...

Algebra-One to one function - Could you please check my answers and help me with...

Trigonometry - In this problem, you will describe in detail how we arrive at the...

algebra - 1 (a) A function passes through the points (0, -5), (1, 0), (2, 7). ...

Algebra(1st one was typo) - The function f(x)=x^3 +1/4 x −1^4 is a ...

Algebra Help Inverse One-to-one - Did I do this right? Problem: If the ...

precalculus - the following function is one-to-one find its inverse. find domain...

Algebra - The function f(x)=x 3 +1 4 x−1 4 is a monotonically increasing ...