The current in a 51 resistor is 0.14 A. This resistor is in series with a 28 resistor, and the series combination is connected across a battery. What is the battery voltage?
R1 = 51 Ohms.
R2 = 28 Ohms.
Vb = V1 + V2 = I*R1 + I*R2,
Vb = 0.14*51 + 0.14*28,
Vb = 7.14 + 3.92 = 11.06 Volts.
Even easier way:
Series R=R1+R2
V=RxI
79x.14=11.06
Well, a resistor is an electrical device that helps you resist the temptation to spend all your money on electronics. In this case, we have two resistors in series, which means they are like two friends holding hands in a line.
But don't worry, they're not just standing there doing nothing. They are actually helping us solve a problem. We know the current flowing through the first resistor is 0.14 A, which is like having 0.14 clowns trying to fit into a tiny car.
Now let's consider the second resistor. Since they are in series, the current flowing through the second resistor is the same. So we still have 0.14 A trying to squeeze into the second resistor.
Now, let's use a little trickery to find the battery voltage. We know that the voltage across a resistor is equal to the current flowing through it multiplied by the resistance.
For the first resistor, the voltage is 0.14 A multiplied by 51 ohms. And for the second resistor, the voltage is 0.14 A multiplied by 28 ohms.
Now, if we add these two voltages together, we get the total voltage across both resistors. That's like adding two clowns together, which is always a recipe for disaster.
So, to find the battery voltage... drumroll, please... we simply add the voltages calculated for each resistor.
(0.14 A * 51 ohms) + (0.14 A * 28 ohms) = Battery Voltage
And that's how we electrify our way to finding the battery voltage. I hope this explanation didn't shock you too much!
To find the battery voltage, we need to use Ohm's Law, which states that the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by the resistance (R):
V = I * R
In this case, we have two resistors connected in series, so the total resistance (R_total) is the sum of the individual resistances:
R_total = R1 + R2 = 51 + 28 = 79 ohms
Now, we can use the given current (0.14 A) and the total resistance (79 ohms) to find the battery voltage:
V = I * R_total
V = 0.14 A * 79 ohms
Calculating this, we get:
V ≈ 11.06 V
Therefore, the battery voltage is approximately 11.06 volts.