Posted by Anonymous on .
If the tens digit of a twodigit number is subtracted from the units digit, the difference is 8. The number with the digits reversed is 10 more than nine times the units digit of the original number. Find the number.

ALgebra...plz help 
tchrwill,
Let the two digit number be 10A + B.
Then, from "If the tens digit of a twodigit number is subtracted from the units digit, the difference is 8.", or
B  A = 8.
From "The number with the digits reversed is 10 more than nine times the units digit of the original number.", 10B + A = 9B + 10.
Substituting A = B  8 into 10B + A = 9B + 10 yields 10B + B  8 = 9B + 10 or 11B  8 = 9B + 10 or 2B = 18 making B = 9.
From B  A = 8, 9  A = 8 making A = 1 or the number = 19. 
ALgebra...plz help 
Anonymous,
too easy

ALgebra...plz help 
Anonymous,
Let unit digit = x
Then tens did it = 8+x
Original no.is 10(8+x)+x
80+10x+x=80+11x
On reversing : 10x+8+x =11x+8
11x+8=10+9x
11x9x=108
2x=2
X=1
No.is 80+11x=80+11=91