Posted by **Anonymous** on Tuesday, February 1, 2011 at 11:23pm.

If the tens digit of a two-digit number is subtracted from the units digit, the difference is 8. The number with the digits reversed is 10 more than nine times the units digit of the original number. Find the number.

- ALgebra...plz help -
**tchrwill**, Wednesday, February 2, 2011 at 10:10am
Let the two digit number be 10A + B.

Then, from "If the tens digit of a two-digit number is subtracted from the units digit, the difference is 8.", or

B - A = 8.

From "The number with the digits reversed is 10 more than nine times the units digit of the original number.", 10B + A = 9B + 10.

Substituting A = B - 8 into 10B + A = 9B + 10 yields 10B + B - 8 = 9B + 10 or 11B - 8 = 9B + 10 or 2B = 18 making B = 9.

From B - A = 8, 9 - A = 8 making A = 1 or the number = 19.

- ALgebra...plz help -
**Anonymous**, Tuesday, August 7, 2012 at 7:46pm
too easy

- ALgebra...plz help -
**Anonymous**, Friday, September 9, 2016 at 4:05am
Let unit digit = x

Then tens did it = 8+x

Original no.is 10(8+x)+x

80+10x+x=80+11x

On reversing : 10x+8+x =11x+8

11x+8=10+9x

11x-9x=10-8

2x=2

X=1

No.is 80+11x=80+11=91

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