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January 29, 2015

January 29, 2015

Posted by **Sam** on Tuesday, February 1, 2011 at 8:06pm.

If f(x)=3x^2 g(x)= 1/6+x find the following and give the domain

(f+g) (x) (3x^2) + (1/6+x)

x is all real numbers and x is not equal to 6

(f-g) (x) (3x^2) - (1/6+x) 3x^2-x-6

x is all real numbers and x is not equal to -6

(f x g) (x) (f/g) (x) 3x^2/6-x

18x^3-x

x is all real numbers

(f/g)(x) 3x^2/ 1/6+x

x is all real numbers; x is not equal to 6

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