Posted by
**Jen** on
.

Graph the Circle

x^2+y^2+4x-2y-20=0

I get:

(x^2+4x)+(y^2-2y)=20

(x^2+4x+4)+(y^2-2y+1)=20+16+4

(x+2)^+(y-1)^2=(40/2)^2

But I don't think its right can you help me with what I did wrong? Thanks

Saturday

March 25, 2017
Posted by
**Jen** on
.

Graph the Circle

x^2+y^2+4x-2y-20=0

I get:

(x^2+4x)+(y^2-2y)=20

(x^2+4x+4)+(y^2-2y+1)=20+16+4

(x+2)^+(y-1)^2=(40/2)^2

But I don't think its right can you help me with what I did wrong? Thanks

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