Posted by Jen on Tuesday, February 1, 2011 at 7:28pm.
Graph the Circle
x^2+y^2+4x2y20=0
I get:
(x^2+4x)+(y^22y)=20
(x^2+4x+4)+(y^22y+1)=20+16+4
(x+2)^+(y1)^2=(40/2)^2
But I don't think its right can you help me with what I did wrong? Thanks

Algebra is my answer right  helper, Tuesday, February 1, 2011 at 7:46pm
(x^2+4x+4)+(y^22y+1)=20+16+4
Should be,
(x^2 +4x + 4)+(y^2  2y +1 )= 20 + 4 + 1
(x^2 +4x + 4)+(y^2  2y +1 )= 25
(x + 2)^2 + (y  1)^2 = 25

Algebra is my answer right  Jen, Tuesday, February 1, 2011 at 7:48pm
Thanks, I see what I did, I squared when adding to the right side
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