Posted by **Jen** on Tuesday, February 1, 2011 at 7:28pm.

Graph the Circle

x^2+y^2+4x-2y-20=0

I get:

(x^2+4x)+(y^2-2y)=20

(x^2+4x+4)+(y^2-2y+1)=20+16+4

(x+2)^+(y-1)^2=(40/2)^2

But I don't think its right can you help me with what I did wrong? Thanks

- Algebra- is my answer right -
**helper**, Tuesday, February 1, 2011 at 7:46pm
(x^2+4x+4)+(y^2-2y+1)=20+16+4

Should be,

(x^2 +4x + 4)+(y^2 - 2y +1 )= 20 + 4 + 1

(x^2 +4x + 4)+(y^2 - 2y +1 )= 25

(x + 2)^2 + (y - 1)^2 = 25

- Algebra- is my answer right -
**Jen**, Tuesday, February 1, 2011 at 7:48pm
Thanks, I see what I did, I squared when adding to the right side

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