Thursday

July 31, 2014

July 31, 2014

Posted by **Ishaan** on Tuesday, February 1, 2011 at 6:21pm.

- Calculus -
**anon**, Tuesday, February 1, 2011 at 7:40pmf(x)= x^2 + bx + 1 on [-1,1]

First, integrate

| = integration symbol

|x^2 + bx + 1 = 1/3 x^3 + 1/2 bx^2 + x + C

Evaluate from -1 to 1

1/3 x^3 + 1/2 bx^2 + x + C

1/3 (1)^3 + 1/2 b(1)^2 + 1 - (1/3 (-1)^3 + 1/2 b(-1)^2 - 1

1/3 + 1/2 b + 1 - (-1/3 + 1/2 b - 1)

1/2 b + 4/3 - (1/2 b - 4/3) = 8/3

Average Value

V = 1/(b - a) * |f(x)

V = 1/(1 - (-1)) * 8/3

V = 1/2 * 8/3

V = 8/6 = 4/3

**Related Questions**

Calculus - I'm supposed to find the average value of the function over the given...

CALCULUs - For all x in the interval [-11,13] the function f is defined by x^3(x...

Calculus - Let f be the function defined by f(x)= x^3 + ax^2 +bx + c and having ...

Calculus HELP!!! - Here is the graph. h t t p : / /goo.gl/PTc2I (spaces added at...

calculus - Consider the function f(x)=–3x3–1x2+1x+1Find the average slope of ...

Calculus Please help! - f(x) -2x^3+2x^2-3x+2 Find the average slope of this ...

calculus - Consider the function f(x)=4sqrtx+5 on the interval [4,5]. Find the ...

Calculus c - Let f be a twice-differentiable function defined on the interval -1...

calculus - Let f be the function defined by f(x)= sqrt(x), 0 <or= x <or= 4...

Calculus Please help! - Consider the function f(x)=4sqrt(x)+4 on the interval [2...