Posted by **Ishaan** on Tuesday, February 1, 2011 at 6:21pm.

If b is a positive constant, find the average value of the function f defined by f(x) = x2 + bx + 1 on the interval [-1,1]

- Calculus -
**anon**, Tuesday, February 1, 2011 at 7:40pm
f(x)= x^2 + bx + 1 on [-1,1]

First, integrate

| = integration symbol

|x^2 + bx + 1 = 1/3 x^3 + 1/2 bx^2 + x + C

Evaluate from -1 to 1

1/3 x^3 + 1/2 bx^2 + x + C

1/3 (1)^3 + 1/2 b(1)^2 + 1 - (1/3 (-1)^3 + 1/2 b(-1)^2 - 1

1/3 + 1/2 b + 1 - (-1/3 + 1/2 b - 1)

1/2 b + 4/3 - (1/2 b - 4/3) = 8/3

Average Value

V = 1/(b - a) * |f(x)

V = 1/(1 - (-1)) * 8/3

V = 1/2 * 8/3

V = 8/6 = 4/3

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