Sunday

March 29, 2015

March 29, 2015

Posted by **Aviana** on Tuesday, February 1, 2011 at 6:17pm.

f(t) = 14sin(1/3t-2) + 60

degrees Fahrenheit. What was the average temperature between 9 am and noon?

- Calculus-parentheses -
**MathMate**, Tuesday, February 1, 2011 at 7:56pmf(t) = 14sin(t/3-2) + 60

∫f(t)dt from 9 to 12

=[ 60*t-42*cos(t/3-2) ] from 9 to 12

=220.17

Average temperature over 3 hours

= 220.17/3

= 73.4°

Note to Aviana:

in the absence of parentheses, multiplications and divisions are performed before additions and subtractions.

Even when 14sin(1/3t-2) + 60 is interpreted correctly as 4sin(t/3-2) + 60, it is a good idea to insert parentheses to emphasize the intention, such as : 4sin((1/3)t-2) + 60

**Answer this Question**

**Related Questions**

calculus - In a certain city the temperature (in degrees Fahrenheit) t hours ...

Algebra - Stella is recording temperatures every day for 5 days. On the first ...

Math - Outside temperature over a day can be modelled as a sinusoidal function. ...

math - The temperature on one day in January for Phoenix, AZ, is 59 degrees ...

precalculus - Outside temperature over a day can be modelled as a sinusoidal ...

math - The temperature outside was 3 degrees Fahrenheit at midnight. During the ...

Math - Problem Solving: Work Backward At 12 noon, Leslie recorded the ...

Math help please - 1. At midnight, the temperature, t, is 13 degrees below zero...

Math - On a winter's day, 9 degrees Fahrenheit is th highest temperature ...

Calculus - The normal body temperature in humans ranges from 97.6 degrees ...