The perimeter of a rectangle is 62 meters. The length is 1 meter more than four times the width. What is the area of the rectangle, in square meters?

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w = width
4w + 1 = length

P = 2w + 2L
62 = 2w + 2(4w + 1)

Solve for w

6 1/10

To find the area of a rectangle, we need to know the length and width of the rectangle. In this case, we have the perimeter of the rectangle, but not the actual length or width. So, let's first set up some equations to solve for the dimensions of the rectangle.

Let's assume the width of the rectangle is "W" meters.

We are given that the length is 1 meter more than four times the width. So, the length is 4W + 1 meters.

The perimeter of a rectangle is twice the sum of its length and width. So, we can set up the equation as:

Perimeter = 2(length + width)

62 = 2(4W + 1 + W)

Now, let's solve for W.

62 = 2(5W + 1)

Dividing both sides by 2:

31 = 5W + 1

Subtracting 1 from both sides:

30 = 5W

Dividing both sides by 5:

6 = W

So, the width of the rectangle is 6 meters.

Now, we can substitute the width back into the equation for the length to find its value:

Length = 4W + 1 = 4(6) + 1 = 25 meters.

Now that we have the length and width of the rectangle (25 meters and 6 meters, respectively), we can calculate the area of the rectangle.

Area of a rectangle = length × width

Area = 25 × 6 = 150 square meters.

Therefore, the area of the rectangle is 150 square meters.