Posted by **Nayyab** on Monday, January 31, 2011 at 10:46pm.

Suppose that f(x) is bounded: that is, there exists a constant M such that abs(f(x)) is < or equal to M for all x. Use the squeeze theorem to prove that lim x^2f(x)=0 as x approaches 0.

if g(x) is Mx^2 then what is f(x) and h(x) according to the squeeze theorem.

Also, what is exactly is the function f(x) because it wants the limit of f(x) times x^2

## Answer this Question

## Related Questions

- calculus - Suppose that f(x) is bounded: that is, there exists a constant M such...
- calculus - Lim sin2h sin3h / h^2 h-->0 how would you do this ?? i got 6 as ...
- calculus - Find the lim x->infinite (x/[3x+5]) where [] denotes the greatest ...
- Calculus (Please Check) - Show that the equation x^5+x+1 = 0 has exactly one ...
- calculus - It is known that x 2 + 4x ≤ f(x) ≤ -x 2 -4x the interval...
- calculus - Prove that the limit as n approaches infinity of ((n!)^2)/(2n)! is 0...
- calculus - A sequence{an} is given by a1=sqrt(2), an+1=sqrt(2*an). a) by ...
- Calculus - use the intermediate value theorem to prove that every real number ...
- Calculus - Suppose f(x)= 7-8x^2, by the Mean Value Theorem, we know there exists...
- calculus - (lim x --> +inf) of (x^2 - [[x^2]])/2 using Squeeze theorem only ...