# calculus

posted by
**Nayyab** on
.

Suppose that f(x) is bounded: that is, there exists a constant M such that abs(f(x)) is < or equal to M for all x. Use the squeeze theorem to prove that lim x^2f(x)=0 as x approaches 0.

if g(x) is Mx^2 then what is f(x) and h(x) according to the squeeze theorem.

Also, what is exactly is the function f(x) because it wants the limit of f(x) times x^2