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Posted by on Monday, January 31, 2011 at 9:03pm.

How do I go about finding the solutions to the following
x^2-6x+25=0

I know the answer is 3-4i and 3+4i
however, I do not know how to go about finding the these solutions
Thanks :)

  • Complex Numbers - , Monday, January 31, 2011 at 10:03pm

    x^2 - 6x + 25 = 0
    Subtract 25 from both sides:
    x^2 - 6x = -25
    Add 9 to both sides:
    x^2 - 6x + 9 = -16
    Factor the left hand side:
    (x-3)^2 = -16
    Take the square root of both sides:
    |x - 3| = 4i
    Eliminate the absolute value:
    x - 3 = -4i or x - 3 = 4i
    Add 3 to both sides:
    x = 3 - 4i or x - 3 = 4i
    Add 3 to both sides:
    x = 3 - 4i or x = 3 + 4i

  • Complex Numbers - , Monday, January 31, 2011 at 11:33pm

    Oh thank you so much
    i forgot that when you that the square root of a negative you get the complex #

  • Complex Numbers - , Tuesday, February 1, 2011 at 2:31pm

    You are welcome

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