Posted by Allie on Monday, January 31, 2011 at 9:03pm.
How do I go about finding the solutions to the following
x^26x+25=0
I know the answer is 34i and 3+4i
however, I do not know how to go about finding the these solutions
Thanks :)

Complex Numbers  helper, Monday, January 31, 2011 at 10:03pm
x^2  6x + 25 = 0
Subtract 25 from both sides:
x^2  6x = 25
Add 9 to both sides:
x^2  6x + 9 = 16
Factor the left hand side:
(x3)^2 = 16
Take the square root of both sides:
x  3 = 4i
Eliminate the absolute value:
x  3 = 4i or x  3 = 4i
Add 3 to both sides:
x = 3  4i or x  3 = 4i
Add 3 to both sides:
x = 3  4i or x = 3 + 4i

Complex Numbers  Allie, Monday, January 31, 2011 at 11:33pm
Oh thank you so much
i forgot that when you that the square root of a negative you get the complex #

Complex Numbers  helper, Tuesday, February 1, 2011 at 2:31pm
You are welcome
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