Posted by **Allie** on Monday, January 31, 2011 at 9:03pm.

How do I go about finding the solutions to the following

x^2-6x+25=0

I know the answer is 3-4i and 3+4i

however, I do not know how to go about finding the these solutions

Thanks :)

- Complex Numbers -
**helper**, Monday, January 31, 2011 at 10:03pm
x^2 - 6x + 25 = 0

Subtract 25 from both sides:

x^2 - 6x = -25

Add 9 to both sides:

x^2 - 6x + 9 = -16

Factor the left hand side:

(x-3)^2 = -16

Take the square root of both sides:

|x - 3| = 4i

Eliminate the absolute value:

x - 3 = -4i or x - 3 = 4i

Add 3 to both sides:

x = 3 - 4i or x - 3 = 4i

Add 3 to both sides:

x = 3 - 4i or x = 3 + 4i

- Complex Numbers -
**Allie**, Monday, January 31, 2011 at 11:33pm
Oh thank you so much

i forgot that when you that the square root of a negative you get the complex #

- Complex Numbers -
**helper**, Tuesday, February 1, 2011 at 2:31pm
You are welcome

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