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Math

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(Factoring a sum or difference of cubes) and (solving a polynomial equation).

2x^3+2=0

  • Math - ,

    2x^3+2=0
    divide by 2
    x^3 +1=0
    now you have a sum of cubes
    (x+1)(x^2-x+1)=0
    x=-1 or x = (1 ± ?-3)/2 or (1 ± i?3)/2

  • Math - ,

    Factor the given equation into:
    2x³+2 =0
    => 2(x²+1)=0

    and use one of the identities:
    x³+y²=(x+y)(x²-xy+y²)
    x³-y²=(x-y)(x²+xy+y²)
    to factor the given equation to linear and quadratic factors.

    Hence solve the resulting linear and quadratic equations.

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