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March 30, 2017

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you will be making hanging flower baskets. the plants you have picked out are blooming annuals and non-blooming annuals. the blooming annuals cost $3.20 each and the non-blooming annuals cost $1.50 each. you bought a total of 24 plants for $49.60. write a linear system of equations that you can use to find out how many of each type of plant you bought.

  • algebra - ,

    b = number of blooming annuals
    n = number of non-blooming annuals
    3.20b = value of blooming
    1.50n = value of non-blooming

    b + n = 24
    3.20b + 1.50n = 49.60

    Solve the system

  • algebra - ,

    i do not think that is what my teacher was asking for.

  • algebra - ,

    "write a linear system of equations"

    This is a linear system of equations.

    You can use x and y instead of n and b.

    x = number of blooming annuals
    y = number of non-blooming annuals
    3.20x = value of blooming
    1.50y = value of non-blooming


    x + y = 24
    3.20x + 1.50y = 49.60

    Then solve the system.
    Have you learned solving simultaneous equations?

    This can also be solved using one equation, but the problem asked for a linear system of equations.

  • algebra - ,

    ya i did today. but i don't understand how you got 24 as the y-intercept

  • algebra - ,

    24 is the total number of plants.

    x = number of blooming annuals
    y = number of non-blooming annuals
    x + y = 24

  • algebra - ,

    okaaaay im starting to get it. so what would the second equation be again? and can you please explain it? =) thanks!

  • algebra - ,

    3.20x = value of blooming annuals
    3.20 each plant * x number of plants = ttl cost
    1.50y = value of non-blooming annuals
    1.50 each plant * y number of plants = ttl cost

    3.20x + 1.50y = 49.60

  • algebra - ,

    ok thanks!

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