# algebra

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you will be making hanging flower baskets. the plants you have picked out are blooming annuals and non-blooming annuals. the blooming annuals cost \$3.20 each and the non-blooming annuals cost \$1.50 each. you bought a total of 24 plants for \$49.60. write a linear system of equations that you can use to find out how many of each type of plant you bought.

• algebra -

b = number of blooming annuals
n = number of non-blooming annuals
3.20b = value of blooming
1.50n = value of non-blooming

b + n = 24
3.20b + 1.50n = 49.60

Solve the system

• algebra -

i do not think that is what my teacher was asking for.

• algebra -

"write a linear system of equations"

This is a linear system of equations.

You can use x and y instead of n and b.

x = number of blooming annuals
y = number of non-blooming annuals
3.20x = value of blooming
1.50y = value of non-blooming

x + y = 24
3.20x + 1.50y = 49.60

Then solve the system.
Have you learned solving simultaneous equations?

This can also be solved using one equation, but the problem asked for a linear system of equations.

• algebra -

ya i did today. but i don't understand how you got 24 as the y-intercept

• algebra -

24 is the total number of plants.

x = number of blooming annuals
y = number of non-blooming annuals
x + y = 24

• algebra -

okaaaay im starting to get it. so what would the second equation be again? and can you please explain it? =) thanks!

• algebra -

3.20x = value of blooming annuals
3.20 each plant * x number of plants = ttl cost
1.50y = value of non-blooming annuals
1.50 each plant * y number of plants = ttl cost

3.20x + 1.50y = 49.60

• algebra -

ok thanks!

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